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Runs tests Onesample runs test & the WaldWolfowitz testOn this page: Onesample runs test Twosample WaldWolfowitz test AssumptionsOnesample runs testThe onesample runs test assesses whether a sequence of observations on a dichotomous variable can be considered random. It is based on the number of runs occurring within the sample. For this test a run is defined as a sequence of adjacent equal observations. More precisely it is a succession of identical observations which are followed and preceded by different observations or by no observation at For large samples the difference between the observed and expected number of runs divided by its standard error has a standard normal distribution. Computations are carried out as follows:
For small samples an exact permutation test can be carried out based upon the distribution of all possible numbers of runs in a sequence of a fixed number of binary digits. This exact test is provided in some packages (for example StatXact). Alternatively the number of runs is compared with that given in the appropriate tables (see Table F in Siegel Uses of onesample runs testFor a dichotomous variable
Twosample WaldWolfowitz testThe same test can be applied to the twosample situation in which case it is known as the WaldWolfowitz test. It functions as an overall test of difference between two independent samples. In other words, the alternative hypothesis is that the distribution of the groups differ in some way  whether location, dispersion, skew or kurtosis. Data from the two samples are combined into a single sample, and arranged into ascending rank order. Data are then coded as 1 for sample one and 0 for sample 2. The test proceeds as in the one sample Ideally there should be no ties in the data used for the WaldWolfowitz test. In practice there is no problem with ties within a group, but if ties occur between members of the different groups then there is no unique sequence of observations. For example the data sets A: 10,14,17,19,34 and B: 12,13,17,19,22 can give four possible sequences, with two possible values for r (7 or 9). The solution to this is to list every possible combination, and calculate the test statistic for each one. If all test statistics are significant at the chosen level, then one can reject the null hypothesis. If only some are significant, then Siegel
AssumptionsSince it is a test of randomness, for once we do not have to assume random sampling to use this test. Nor are there any distributional assumptions. But the following assumptions are made:
Various weaknesses and drawbacks of the runs test have been identified:
This test is conditional upon the observed frequency of each type of observation  it makes no predictions regarding what might happen if other frequencies were observable. It also ignores the possibility of any sort of classification error  random or systematic. In order to test the null hypothesis all observations are assumed to be equally likely to appear in any order. If the nature of your observations makes this outcome unlikely that confounding factor will bias this test's Notice also this test does not distinguish where runs occur in a sequence  nor the length of those runs  nor how much the runlengths vary. Last but not least, where data are collapsed to a binary classification, this test makes no allowance for how the breakpoint was decided upon  nor how far the original values deviate from that breakpoint.
