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Just a note

You can equally well apply this logic to the likelihood of buying just three lottery tickets - all of which win the jackpot. Where the probability of an event is constant, the likelihood is simply Pn.

If the likelihood of getting one winning ticket is 0.00001, then the chance (assuming the lottery draw is not 'fixed') of obtaining 3 out of 3 winning tickets is 0.0000013, or about 1 in a hundred million million. Of course, the highest likelihood n events can possibly have is just 1. Or, if you prefer, given P is the probability of an event occurring, and Q is the probability of it not occurring, then P + Q = 1. Therefore the probability of all possible occurrences in n events is [P+Q]n = 1, our familiar binomial formula.