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Just a note

95% CI ()    =    ± t(1 − α/2) s
√n

where:
  • t1 − α/2 is a quantile of the t distribution with (n − 1) degrees of freedom,
  • α is the significance level; for a 95% confidence interval α = 0.05.
  • s is the standard deviation of the observations,
  • n is the number of observations.