|CL = ||[1 + F0.025,v1,v2(q + 1/n)/p]−1|
and F has v1 and v2 degrees of freedom: v1 = 2(nq + 1) and v2 = 2np.
|CU = [1 + ||q||]||−1|
|(1/n + p)F0.975,v3,v4|
and F has v3 and v4 degrees of freedom, v1 = 2(np+1) and v2 = 2nq
- F0.975 is the quantile below which 0.975 of that F-distribution lies.
N.B. If you are using published tables, look up F0.025 - in other words the quantile above which 0.025 of that F-distribution lies.
- CL and CU are the lower and upper 95% confidence limits
- p and q are the proportions in the sample with and without the character of interest,
- n is the sample size,